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Solve the question with steps.-Pls frnds it's urgent.

1) Find using the compound interest formula p[1+(r/100)]^n:

a)Find the principal f the Compound interest is compounded annually at the rate of 10% per annum for 3 yrs is Rs.331.

b) What sum of money will amount to Rs.2704 in 2 years at 4% per annum.



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A=P[1+ \frac{r}{100} ]^{n}\\ \\P+331=P[1+ \frac{10}{100} ]^{3}\\ \\P+331=P[1.1]^{3}\\ \\P+331=1.331P\\ \\1.331P-P=331\\ \\0.331P=331\\ \\P= \frac{331}{0.331} =\boxed{Rs.\ 1000}

Principal = Rs. 1000

A=P[1+ \frac{r}{100} ]^{n}\\ \\2704=P[1+ \frac{4}{100} ]^{2}\\ \\2704=P[1.04]^{2}\\ \\2704=1.0816P\\ \\P= \frac{2704}{1.0816} =\boxed{Rs.\ 2500}

The sum of money is Rs. 2500
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