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A cricket ball of mass 150g is moving with a velocity of 12m/s and hitted by a bat so that the ball is turned back with a velocity of 20m/s. if the

duration of contact btw the ball and bat is 0.01s.then:
1. the impulse is----------------------
2.avg force exerted by bat is
then the of the ball
then the ball ret arda tion is


Impulse= change in momentum of the body =  \frac{m(v-u)}{t} = \frac{150(-20-12)}{.01} Ans is( -) 480000...... Direction of net impulse is represented by the negative sign .....
1 4 1

0 0 0
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