A cricket ball of mass 150g is moving with a velocity of 12m/s and hitted by a bat so that the ball is turned back with a velocity of 20m/s. if the duration of contact btw the ball and bat is 0.01s.then:
1. the impulse is----------------------

2
2.avg force exerted by bat is
then the of the ball
then the ball ret arda tion is

Answers

2015-02-05T10:36:46+05:30
Impulse= change in momentum of the body =  \frac{m(v-u)}{t} = \frac{150(-20-12)}{.01} Ans is( -) 480000...... Direction of net impulse is represented by the negative sign .....
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2015-02-06T09:57:43+05:30

impulse=m(v2-v1)
=150(-20-12)=150×(-32)=4800
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