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Find the heat needed to convert 10g of ice at 0 celsius to water at 20 celsius.

Given: Latent heat of fusion of ice=336* 10^{3} j/kg; specific heat of water= 4200 J/kg-k.


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10g=0.01kg For converting 0 degrees ice to 0 degree water the amount of heat is Q=mlf =0.01*336000 =3360 For converting 0 degrees water to 20 degrees water is Q=mass*specific heat*temparature difference =0.01*4200*(20-0) =840 Total heat =3360+840 =4200
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