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In a leap year find the probability that there are 53 Tuesday in year

There are total 366 days in a leap year. [ 52 weeks ( 7 days ) and 2 days ]

There are 7 days in a week. Then the probability that the remaining is a Tuesday

P(E) = 2/7
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There are 52 weeks in a leap year with two days left day 52*7=364 364+2=366 So these two days can be Monday Tuesday or Tuesday Wednesday or Wednesday Thursday and so on Total outcome =7 Favorable one=2 So probability is =favourable /total P(E) =2/7
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