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**(1+2+3+...50 terms)-(6+7+8...50 terms) ------------ equation**

**so now these are in ap**

**for (1+2+3+...50 terms) n=50, a=1 and d=1**

**by the formula Sn = n/2(2a+(n-1)d)**

**=50/2(2(1)+(50-1)1)**

**=25(51) ---------------------- 1**

**similarly for (6+7+8...50 terms) n=50, a=6, d=1**

**by placing this in formula we get 50/2(2(6)+(50-1)1)**

**= 25(12+49)**

**= 25(61) --------2**

**by adding 1 and 2 we get the value by the equation formed at first**

**= 25(51)-25(61)**

**= 25(51-61)**

**= 25(-10)**

**= -250**

**therefore, the value of given expression is -250**