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The area of rhombus is equal to the area of a triangle whose base and the corresponding altitude are 25m and 16 m respectively. If one of the diagonals of

the rhombus is 40 m, find the length of the other diagonal.



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Area of triangle =  \frac{1}{2}bh
Area of rhombus =  \frac{1}{2}d_1d_2
where d₁ and d₂ are the diagonals of a rhombus.

given that b=25, h=16 and d₁=40

 \frac{1}{2} bh= \frac{1}{2} d_1d_2\\ \\ \Rightarrow 25 \times 16=40 \times d_2\\ \\ \Rightarrow d_2= \frac{25 \times 16}{40}\\ \\ \Rightarrow d_2 =\boxed{40m}

Length of other diagonal is 40m.

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