Let the total number of coins be N. N = 36.

Let there be n number of 10 paise coins. Their value n * 10 paise

let there be m number of 25 paise coins. Their valie m * 25 paise

So, there are (N - m - n) number of 5 paise coins.

Their value (N-m-n) * 5 paise = (36 - m - n) * 5 paise = 180 - 5 m - 5 n paise

The total value: 25 m + 10 n + 180 - 5 m - 5 n = 300 paise

20 m + 5 n = 120

4 m + n = 24

n = 60 - 4 m = 4 (6 - m)

Thus n is a multiple of 4.

we also say that there is at least one 25 paise, at least one 5 paise and at least one 10 paise coin present.

1)

n = 4: m = 5

there are 4 of 10 paise, 5 of 25 paise, and 27 of 5 paise coins.

2) n = 8 , m = 4

so there are 8 of 10 paise, 4 of 25 paise, and 24 of 5 paise coins.

3) n = 12 , m = 3

so there are 12 of 10 paise, 3 of 25 paise, and 21 of 5 paise coins

4)

n = 16 , m = 2

so there are 16 of 10 paise, 2 of 25 paise coins, and 18 of 5 paise.

5)

n = 20 m = 1

there are 20 of 10 paise , 1 of 25 paise coins, and 15 of 5 paise coins.