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2015-02-20T22:05:55+05:30

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Let there be m of 25p coins, and p number of 5paise.
  Then there are n = 36 - m - p number of 10p coins.
  Assume that there is at least 1 of each type of coin.

Their total value in paise is :
       25 m + 10 n + 5 p = 300 paise
        25 m + 10 (36 - m - p) + 5 p = 300
             5 p = 15 m + 60

     p = 3 m + 12

As   m >= 1,    p >= 15  and  p is a multiple of 3.   m , n , p are all integers.

    m = 1       p = 15      n = 36 - 15 - 1 = 20
    m = 2       p = 18      n = 16
    m = 3         p = 21     n = 12
    m = 4        p = 24      n = 8
     m = 5        p = 27     n = 4

  So there are five combinations of coins possible.

1 5 1