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2 bulbs of 500w and 200w are manufactured to operate on 220v line.What will be the ratio of heat produced in 500w and 200w bulb , when they are joined a)in

parallel b)in series


The Brainliest Answer!
The resistances are 96.8 ohm and 242 ohm
a) in parallel
potential difference is same
so the ratio is 242/96.2
b) in series
current is same
so it is 96.2/242
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Heat produced = i^{2} rt=(v^{2} /r)t
calculate resistances using power=vv^{2}/r
a)in parallel combination v is same
    heat ratio can be calculated as h_{1} : h_{2} =r_{2} :r _{1}

b)similarly in series current is same
[tex] h_{1} : h_{2} [/tex]=v _{1} ^{2}* r_{2}  :v _{2} ^{2}* r_{1}
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