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The Brainliest Answer!
2014-04-18T19:29:03+05:30
The formula for sum of square of natural numbers isĀ 
 \frac{n(n+1)(2n+1)}{6}
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2014-04-18T19:30:01+05:30
1^2 + 2^2 + 3^3 + ..... N^2 = [(n)(n+1)(2n+1)] / 6
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