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2015-02-25T20:26:19+05:30

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Let x be the breadth of the rectangle.
As area of square is 49 cm^2, its side is 7 cm.
Perimeter of square = 28 cm.
Perimeter of rectangle = 2(9.3 + x) = 28 cm
Thus, x = 4.7 cm
Are of rectangle = 4.7 * 9.3 = 43.71 cm^2
Thus, the square has greater area.

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2015-02-25T20:32:15+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Let area of square be x^2
and here x^2=49
x=+-7
since length can't be negative so a=7
and we know that
perimeter of  rectangle = perimeter  as square(.given)
length of rectangle =9.3(given)
perimeter of square =4x (where x is the length of side)
plugging in the values
and perimeter of rectangle=2(l+b) where l is length and b is breadth
we get
4x = 2( l + b )  
plugging in the given values we get
4*7=2(9.3+b)
28=18.6+2b
28-18.6=2b
9.4/2=b
b=4.7 
area=l*b
=4.7*9.3
4.7 * 9.3 = 43.71
hence 49>43.71
so square has more area

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