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A cylindrical vessel open at the top has a base of radius 10.5cm and height 14cm find the cost of painting the inner part of the vessel at the rate of ₹10

per sq.cm take22/7 as  \pi



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R = 10.5 cm
h = 14 cm
inner area = inner curved surface area  + base area
               = 2πrh + πr²
               = 2×(22/7)×14×10.5 + (22/7)×10.5²
               = 1270.5 cm²
rate = ₹10 per cm²
cost = 1270.5×10 = ₹12705
2 5 2
R=10.5 cm
h=14 cm
   inner area=base area+inner curved area
base area=πr²=22/7*10.5²=346.5 cm²
Inner curved area=2πrh=2*22/7*10.5*14=924 cm²
then inner curved area=346.5+924=1270.5 cm²

10 ruppee per cm²\
so total cost=10*1270.5=12705 ruppee
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