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Oxidation of Hydrogen is 1.So there are three molecules of hydrogen.So oxidation
number of H3 = 3(1) = 3

So we need to make the overall oxidation number of NH3 should be zero as it is in its free state.

So only 3(O.no of H3) + __ (O.no of N) = 0
3+O.no of N = 0
O.no of N = -3

In this method oxidation of different compounds can be found.

2 5 2
Oxidation number of hydrogen is 1 (we know)
and total charge is zero so
if you are considering  about n3h
then oxidation number is
let consider n be "x"
so oxidation number of n3h is =-1/3
0 0 0
ok i will ask another question
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u also helped me so much thanks
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