Answers

2015-03-01T16:38:22+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Now the half life of the isotope is given 2 hours. After 6 hours the no of half lives will be 3.

So the The amount of radioactive isotope remaining can be calculated as:

Nt = No x 1/2^n where, Nt is the amount of radio isotope remaining. No is the original amount of radio isotope.

N is the no of half lives.

Now let the original amount of isotope is one, then by using the formula we can calculate the remaining of isotope as:

Nt = 1x1/2^3

= 1x1/8

= 1/8
0
2015-03-01T16:47:11+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
If initial quantity of a radioactive isotope is N₀, after n complete half lives, the quantity remaining will be  \frac{N_0}{2^n} .

Half life = 2 hours
time = 6 hours
number of half lives = 6/2 = 3

So quantity of isotope left behind =  \frac{N_0}{2^3}= \frac{N_0}{8}

So only  \frac{1}{8} of the initial quantity will remain after 6 hours.
0