Free help with homework

Why join Brainly?

  • ask questions about your assignment
  • get answers with explanations
  • find similar questions


 x^{2} (px+q)-rx-1=0
as for cubic equation
 abc= \frac{-r}{p}
ab+bc+ca= \frac{r}{p}
now the value of determinant is
 abc= \frac{-r}{p}
ab+bc+ca= \frac{r}{p}
ab+bc+ca+abc= \frac{r}{p}- \frac{r}{p}=0
So the Value of determinant is zero

2 4 2
The value of determinat is abc(1+1/a+1/b+1/c)
found using elementary operations
and form the cubic equation u can say that it is 0
0 0 0
The Brain
  • The Brain
  • Helper
Not sure about the answer?
Learn more with Brainly!
Having trouble with your homework?
Get free help!
  • 80% of questions are answered in under 10 minutes
  • Answers come with explanations, so that you can learn
  • Answer quality is ensured by our experts