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I was absent to progressions class plz any body explain in easy way so i can do my problems easily plzzzz frnds help me....

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Arithmetic progression is a sequence of numbers in which the difference between any two consecutive terms is always constant.
For example: 1,3,5,7,9,11.....; 16,13,10,7....

In 1,3,5,7,9,11.....,
first term = 1
common difference = 3-1 = 2

in 16,13,10,7.....
first term = 16
common difference = 13-16 = -3

you can find the common difference by subtracting any two consecutive number. Given the first term(a) and the common difference(d), you can calculate the nth term of the AP(a_n) and sum of n terms of the AP(S_n).


S_n= \frac{n}{2}[2a+(n-1)d] =\frac{n}{2}[a+a_n]
2 5 2
do examples. otherwise you won't understand properly.
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