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Please answer fast got exam the next day seequestion in the attachment.

in the following figure, Q is the midpoint of BCand QP and QR are perpendiculars to AB andAC respectively. Also AB=AC Prove that : (1)ΔBPQ IS CONGRUENT TO ΔCRQ (2)BP=CR

In triangle PQB & triangle RQC BP=CR angle P= angle R ( each 90 degree) BQ=QC (as Q is the midpoint of BC) By SAS congruence rule: triangle BPQ is congruent to triangle CRQ PROVED

In ΔBPQ and ΔCRQ angle P=angle R(since both are right angles given) BQ=QC(since Q is the midpoint of BC it divides BC into equal halves) BP=RC(since they are the parts of AB and AC and AB and AC are equal)

Therefore ΔBPQ is congruent to ΔCRQ by SAS congruency