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2015-03-07T20:41:36+05:30

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Since the power is 2n so the total terms is (2n+1)

so middle term is (2n + 1)/2

so (x³ - 3x² +3x - 1) ^{2n}

⇒ (x-1) ^{6n}

so total terms is 6n + 1

so middle term is (6n + 1 + 1)/2 = 3n + 1

so T_{3n+1}=^{6n}C_{3n}x^{3n}*-1^{3n}

- \frac{6n!}{3n!3n!}x^{3n}  is n is odd

else 

\frac{6n!}{3n!3n!}x^{3n} if n is even

0
Got it
thats same
i have just divided the answer when n is odd and even
How did (x-1)^6n had come
factorize 1-3x+3x^2-x^3 u will get (1-x)^3