159

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159

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which is

5x-7y+19=0 and intersects the line 7x+5y+12=0

at point (-1,-0.986)

this point acts as midpoint for point and reflection point

so reflection point is

(-8,-8.973)

i.e. 5x-7y+19. Since it is perpendicular and not parallel it will insect line 7x+5y+12 = 0 at

the point (-1,-0.986). This point can be the midpoint, thus reflection point will be (-8,-8.973). Hope this will help you.......