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In a one day cricket match ,sachin played 40 balls and hit 12 sixes and saurabh played 30 balls and hit 9 fours. find the probability that sachin will hit

a six in the next ball and also find the probability that saurabh will not hit four in the next ball.



total balls=40
number of sixes=12
probability of six=12/40=6/20=3/10

total balls =30
number of fours=9
so number of other balls=30-9=21
probabiity to not four= 21/30
1 4 1
why both the ans seems to be different
coz its wrong
u also will be knowing that probablity = no of event / total number of observations and see what he has done total number of observations/no of event
see what u have typed
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