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As for inverse function
take f^{-1}(x)=y

 \frac{y^2-4y+2}{3y}=x \\ y^2-4y+2=3xy \\ y^2-4y=(3x+4)y \\ (y-4)=3x+4 \\ y=3x+8
therefore inverse function is 3x+8
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