Answers

2015-03-10T23:47:15+05:30
You mean
 1^2+ 2^2+3^2 +... n^2 = ..? 

Then its equal to
 \frac{n(n+1)(2n+1)}{6}
1 5 1
2015-03-11T12:51:07+05:30
The sum of the squares of the first 'n' natural numbers

1² + 2² + 3² + 4² + 5² ..............

 \frac{n(n+1)(2n+1)}{6}
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