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According to the question, the wire is in the form of a cylinder,

a)Thus volume of cylinder = πr²h = 3.14 x 0.1² x 3600 = 113.04cm³

b) The volume of sphere will be equal to that of the wire as the sphere is molded from it So, 4/3πr³ = 226.28 = 4/3 x 3.14 x r³ = 226.28 = r³ = 113.04x 3/(4 x 3.14) = r³ = 54 = r = √54 = 3.77cm

c) We know that volume of wire and sphere are equal. Thus volume of sphere = 226.08cm³

The radius of sphere is 3 cm and v of sphere is 113.04 and v of wire=113.04 NOW, wire is cylindrical v=pie r sq. h=>3.14*1/10*/10*3600=113.04 v of the cylinder(wire) is 113.04 YOU KNOW V. OF WIRE=V. OF SPHERE and v of the sphere will be 113.04 so,,, v of sphere=2/3 pie r cube pie r cube=113.04*3/2 r cube=113.04*3/2/3.14 r cube=54.00 r=cube root of 54=>3.77 <> >r of sphere=3.77 cm