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As the question incomplete,
Assuming that the points P, Q and R are collinear.

So, the area of ΔPQR is 0

Area of triangle =  \frac{1}{2}|x_1(y_2-y_3) + x_2(y_3-y_1)+x_3(y_1-y_3)|

                      0 =  \frac{1}{2}|1(0-b) + 0(b-2)+a(2-0)|
                     0  = |-b + 0+ 2a|
                     2a = b

Option C is correct answer.

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