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A certain group of students uses internet service for a monthly charge of Rs 4,800 . If 4 more students join the group , each person would pay Rs 200 less.

Find the number of students in the group in the beginning.

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Let the number of students is x and per student pay Rs. y per month so x*y = 4800 ------------(1) as 4 more students join and each pay 200 less so (x+4)(y-200) = 4800 x*y - 200x + 4y - 800 = 4800 put the value of x*y from the (1) equation 4800 - 200x + 4y - 800 = 4800 50x - y - 200 = 0 y = 50x + 200 -------------(2) put the value of y from (2) equation in the (1) equation x(50x + 200) = 4800 50x² + 200x = 4800 x² + 4x - 96 = 0 x² + 12x - 8x - 96 = 0 x(x + 12) - 8(x + 12) = 0 (x+12)(x-8) = 0 x+12 = 0 x = -12 or x-8 = 0 x = 8 as the number of students can not be negative so at the beginning number of students = 8 and per students pay 8*y = 4800 y = Rs. 600 in the beginning