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2015-03-14T00:18:17+05:30

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Acc. to the attached fig.
AOD=180-95=85°
 AXD=85/2=42.5°( As X is on the circumference , AXD will be half the Angle at the centre)
AXO=XAO( both are radi, therefore they are equal, hence form an isosceles triangle)
AXO=XAO=42.5°.............(i)

BOD=95°
 BXD=95/2=47.5°
BXO=XBO(------DO------)
BXO=XBO=47.5°..........(ii)

ACB=90°(  angle subtended by the diameter)
 ABC=90-x....(iii)

Now, AXBC forms a cyclic quad.
So, A+B=180
   x+42.5=47.5+90-x
2x=95
x=42.5
 
So, the crrt option wud be E) None.
 


2 3 2
AOD=85 so AXD=85/2
this is wrong answer plzz delete it
wrong
it must be deleted
this must be deleted
2015-03-14T23:13:22+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
given :-
bod = 95  ,
o is center  and
ab is diameter

solution :-

BOD=95°
 BXD=95/2=47.5°
BXO=XBO(------DO------)
BXO=XBO=47.5°    -1   

ACB=90 °(  angle subtended by the diameter)
 ABC=90-x.         -2

AOD=180-95=85°
 AXD=85/2=42.5°( As X is on the circumference , AXD will be half the Angle at the centre)
AXO=XAO( both are radi, therefore they are equal, hence form an isosceles triangle)
AXO=XAO=42.5°    -3

Now, AXBC forms a cyclic quad.
So, A+B=180
   x+42.5=47.5+90-x
2x=95
x=42.5
 
hence option e is the answer

3 3 3
u have copied it...
from tanisq..
arnav bro compare it both r different
some lines are copied
this must be deleted