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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

We know that the maximum probability for a task is 100. So let the probability of winning the game be x and that of losing be y.

So we have two equations: i) 2y + 1/3 = x ; 6y + 1 = 3x ii) x + y = 100 ; x = 100 - y

Now putting the value of x in (ii) in (i), we have, 6y + 1 = 3(100-y) = 6y + 1 = 300 - 3y = 9y = 299 = y =299/9 = 33.22% (losing) Therefore, probability of winning = 100 - 33.22 = 66.78%