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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Given:AD is the median of triangle ABC.E is the mid point of AD.BE produced meet ad at F. to prove:AF=1/3AC. Construction:From point D draw DG parallel to BF. Proof: so by Convere of mid point theorum we get F as the mid point of AG ⇒AF=AG(1) similarly we have G as the mid point of CF ⇒FG=GC(2) from 1 and 2 we get AF=FG=GC (3) now AF + FG + GC =AC From (3) we get AF+AF+AF=AC 3(AF)=AC AF=1/3AC hence prove . Hope this helps

Given: AD is the median of triangle ABC. E is the mid point of AD.BE produced meet ad at F. RTP ::AF=1/3AC. Construction:From point D draw DG parallel to BF. solution : By mid point theorem we got F as the mid point of AG -> AF=AG --------1 G as the mid point of CF -> FG=GC--------------2 by one and two AF = FG= GC ---------- 3

now , AF + FG + GC =AC by the 3 rd equation AF+AF+AF=AC 3×AF =AC so 1/3 ac = af