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The formula for finding the sum of the interior angles of any polygon is (n-2) x 180 where n is the no. of sides the polygon has. So the sum of the interior angles of a rectangle would be (4-2) x 180 2 x 180 = 360 degrees So the measure of one angle would be 360/4 (because there are four angles in a rectangle) = 90 degrees Don't forget to thank me if it was helpful :)

Consider a rectangle ABCD join BD and AC now,consider the triangle ABD and BAC AB=AB (common) AD=BC AC=BD(diagonals of a rectangle are equal) therefore,<A=<B (CPCT)....................................................(1) now consider the triangle ABCD as it is a parallelogram,the adjacent angles are supplementary i.e.<A+<B=180.............................................................(2) But,<A=<B so, 2<A=180 <A=90 hence,<b=90 too' llly,we can prove the rest.. :)

in order to prove each angle as 90, it should be a IIgm else u cant prove any random quad. as a rectangle with unequal diagonals

:)

as in this case, we use the property of equal diagonal of a parallelogram which bisect each other, so other way such a fig. formed has to be a parallelogram