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Two workers A and B working together completed a job in 5 days. If A worked twice as efficiently as he actually did and B worked 1/3 as efficiently as he

actually did, the work would have been completed in 3 days. To complete the job alone , A would require
Why can't i post an answer here?


let A can do alone the work in x days
let B can do alone the work in y days
A's 1 day work =1/x
B's 1day work  =1/y
(A+B)'s 1day work =1/5
therefore,1/x+1/y=1/5    ------------(1)
A had worked as efficiently as he actually did nd B had worked 1/3 as he actually did
A's 1day work =2/x
B's 1day work =1/3y
(A+B)'s 1 day work =1/3
therefore,2/x+1/3y=1/3 ----------------(2)
solving eqn (1) nd (2)
we get x=6.25
there fore A can alone work in 6.25 days

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