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2015-03-31T16:10:27+05:30

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Mean(m) = 662 kg
sd = 32 kg

for x=600 kg, z =  \frac{600-662}{32}=-1.9375
for x=750 kg, z =  \frac{750-662}{32} =2.75

Using Z table:
P(z < -1.9375) = 0.0268
P(z < 2.75) = 0.9970

P(-1.9375 < z < 2.75) = 0.9970 - 0.0268 = 0.9702

So probability of a land with yield between 600 kg and 750 kg is 0.9702
total plots = 1000
Number of plots with expected yield between 600 and 750 kg is given by
N = 1000×0.9702 = 970.2 ≈ 970
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