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P = Rs 12,000 After one year the sum accumulated with compound interest = P (1 +r/100) = 12,000+120 r Rs 4,000 is returned. Remaining amount = 8,000 + 120 r at the end of 1st year.

Sum accumulated at the end of 2nd year = (8,000+120r)(1 + r/100) = 8,000 + 200 r + 1.2 r² I am not sure if the compound interest for the second year is to be taken as : 8,000 + 200 r + 1.2 r² - (8,000 + 120 r) = 1.2 r² + 80 r

hence, 1.2 r² + 80 r = 920 => 3 r² + 200 r - 2300 = 0 3 r² +230 r - 30 r - 2300 = 0 (3 r + 230) r - 10 (3 r + 230) = 0 r = 10 % as r is positive we ignore the negative root.

accumulated sum at the end of 2nd year = 8,000 + 200 * 10 + 1.2 * 10² = Rs 10,120