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An aeroplane leaves an airport and flies due north at a speed of 1000kmph.At same time another airplane leaves the same airport and flies due west at a

speed of 1200kmph.How far apart will be the 2 planes after 1 and half hours?

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Let the point of departure be A. Let the aeroplane towards the North be at N and the aeroplane towards the West be at E after 1 and half hours. the distance AN = 1000 * 1.5 = 1500 km the distance AW = 1200 * 1.5 = 1800 km

ANW is a right angle triangle. NW is the diagonal. NW² = AN² + AW² = 1500² + 1800² NW = 2, 343.075 km

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

The two planes are 2,343.07 km apart.
See the attachment for calculations.

Distance covered by the first plane in 1.5 hours = 1500 km

Distance covered by the second plane in 1.5 hours = 1800 km The position of the two planes after 1.5 hour journey can be shown by a right triangle and we need to find the hypotenuse to know the aerial distance between them. Here; h = ? p = 1800 km and b = 1500 km From Pythagoras theorem; h2 = p2 + b2Or, h2 = 18002 + 15002= 3240000 + 2250000 = 5490000Or, h = 300√61 km