# A conductor carries the current of 0.2A. find the amount of charge that will pass through the cross - section of conductor in 30 minutes. how many electrons will flow in the same time interval.

2
by tanishq1999

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by tanishq1999

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Time(t) = 30 min = 30 * 60 = 1800 Sec.

I = Charge / t

0.2 = Charge / 1800

Charge(Q) = 0.2 * 1800 = 360 C

I = no of electrons(n) * charge on electrons / t

0.2 = n * 360 / 1800

0.2 * 1800 / 360 = n

n = 1

current(I)=charge(q)/time(t)

0.2=q/(30*60)

q=0.2*30*60

q=360 C

but,

1 C=6.2415*(10^18)

then

360 C=360*6.2415*(10^18)=n

n=2246.94*10^18=224694*10^16

therefore,224694*10^16 electrons flow in the same time interval given.

hope this may be correct......!