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2015-03-25T00:03:57+05:30

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Let a be the side of the square.  Then its diagonal is given by the pythagoras theorem,

   diagonal² = a² + a² = 2 a²
  diagonal = √2 a  = 5 cm
   => side = a = 5/√2 cm = 2.5 √2 cm
 
hence, there is only one square is possible with a diagonal of 5 cm .
2 3 2
2015-03-25T10:16:33+05:30
Let s =  side of the square.

Diagonal² = s² + s² = 2 s²
Diagonal =
 √2 s  = 5 cm
 s =  \frac{5}{ \sqrt{2} }  
s =  \frac{5 \sqrt{2} }{2}
 
Hence, only one square is possible with a diagonal of 5 cm .
1 5 1