# What is total resistance, between A and B in the circuit shown in the given figure

by biju64george 25.03.2015

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by biju64george 25.03.2015

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Resistance of AF and FE are in series. So total = 2+2 = 4 ohm

Now it is in parallel with AE(4 ohm).

So effective resistance between A and E is ohm.

Now it is in series with ED(2 ohm). So total = 4 ohm which is in parallel with AD(4 ohm). So effective resistance between A and D is 2 ohm.

It goes on and finally the effective resistance between A and B is 2 ohm.

Now it is in parallel with AE(4 ohm).

So effective resistance between A and E is ohm.

Now it is in series with ED(2 ohm). So total = 4 ohm which is in parallel with AD(4 ohm). So effective resistance between A and D is 2 ohm.

It goes on and finally the effective resistance between A and B is 2 ohm.

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Effective resistance between A and B:

Resistance along AFE: 4 ohms.

it is in parallel with 4 ohms along AE. Hence, effective resistance of these two:

= 4 * 4 /(4+4) = 2 ohms

resistance along AED: 2 ohms + 2 ohms = 4 ohms.

This is in parallel with the resistance along AD : 4 ohms.

Hence the effective resistance : 2 ohms .

This is in series with resistance 2 ohms along CD. HEnce, total resistance along ADC is 4 ohms.

This is parallel with the 4 ohms resistance along AC. Effective resistance then is 2 ohms. This is in series with 2 ohms along BC.

Hence the along ACB the resistance is 4 ohms.

Between A and B there are two 4 ohms resistances in parallel.

Hence,*effective resistance between A and B = 2 ohms*.

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effective resistance between A and D:

Total resistance along ABC = 6 ohms.

Between A and C we have 4 ohms and 6 ohms in parallel.

equivalent Resistance between A & C along AC: 6*4/(6+4) = 2.4 ohms

Add this to the resistance 2 ohms between C and D. Hence, Along ACD the resistance is 4.4 ohms.

similarly, on the other side, Equivalent resistance along AED will be 4.4 ohms, from symmetry.

Now, 4 ohms between A and D, 4.4 ohms along AED, and 4.4 ohms along ACD are all in parallel.

equivalent resistance along AD: R (say).

1/ R = 1/4 + 1/4.4 + 1/4.4 = (1.1 +1+1)/4.4 = 3.1/4.4

* R = 4.4 / 3.1 ohms = 1.42 ohms.*

Resistance along AFE: 4 ohms.

it is in parallel with 4 ohms along AE. Hence, effective resistance of these two:

= 4 * 4 /(4+4) = 2 ohms

resistance along AED: 2 ohms + 2 ohms = 4 ohms.

This is in parallel with the resistance along AD : 4 ohms.

Hence the effective resistance : 2 ohms .

This is in series with resistance 2 ohms along CD. HEnce, total resistance along ADC is 4 ohms.

This is parallel with the 4 ohms resistance along AC. Effective resistance then is 2 ohms. This is in series with 2 ohms along BC.

Hence the along ACB the resistance is 4 ohms.

Between A and B there are two 4 ohms resistances in parallel.

Hence,

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effective resistance between A and D:

Total resistance along ABC = 6 ohms.

Between A and C we have 4 ohms and 6 ohms in parallel.

equivalent Resistance between A & C along AC: 6*4/(6+4) = 2.4 ohms

Add this to the resistance 2 ohms between C and D. Hence, Along ACD the resistance is 4.4 ohms.

similarly, on the other side, Equivalent resistance along AED will be 4.4 ohms, from symmetry.

Now, 4 ohms between A and D, 4.4 ohms along AED, and 4.4 ohms along ACD are all in parallel.

equivalent resistance along AD: R (say).

1/ R = 1/4 + 1/4.4 + 1/4.4 = (1.1 +1+1)/4.4 = 3.1/4.4