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2015-03-25T23:52:31+05:30

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H = 14cm
V = 176 cm³
⇒ πr²h = 176
⇒ r² = 176/(14π) = 4
⇒ r = √4 
⇒ r = 2cm

difference between the inner and outer surface of a cylendrical pipe is 88sq cm
2 \pi h(r_o-r_i)=88\\ \\ \Rightarrow (r_o-r_i) = \frac{88}{2 \times 14 \times 3.14}  \\ \\ \Rightarrow (r_o-r_i) =1\\ \\ \Rightarrow r_o=1+r_i=1+2\\ \\ \Rightarrow r_o=3\ cm

Inner radius = 2cm
Outer radius = 3cm
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