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A metallic box is in the shape of solid having dimensions 200cm*50cm*100cm.it is recast into solid cube.find the differences of surface area of two solids

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We know that the volume of a cuboid = l x b x h Therefore, volume of metallic box = 200 x 50 x 100 = 1000000cm³

Now, when the box is recasted into a cube, the volume will remain the same. So, the volume of the cuboid formed = 1000000cm³. Thus, it each side = ∛1000000 = 100cm

Total surface area of the cuboid = 2(lb + bh + hl) = 2(200 x 50 + 50 x 100 + 100 x 200) = 2(10000 + 5000 + 20000) = 2 x 35000 = 70000cm²

Total surface area of the cube = 6a² = 6 x 100 x 100 = 60000cm²

Difference in their surface areas = 70000 - 60000 = 10000cm²

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

volume of cube = volume of cuboid a³ = lbh a³ = 200×50×100 a³ = 1000000 a=100cm so, tsa of cuboid = 2(lb+bh+hl) = 2(200×50+50×100+100×200) = 2(10000+5000+20000) = 2(35000) = 70000cm² tsa of cube = 6a² = 6(100)² = 60000cm² then differences in their sa's = 70000-60000 = 10000cm²