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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

We know that the area of a triangle is half of that of a parallelogram if they are on the same base and between the same parallels. In case triangle XCB, base is half. Therefore, area of triangle XCB = 1/2 x 1/2 ar(ABC) =1/4 ar(ABC)

Now ar(AXCD) = ar(ABCD) - ar(XCB) = 1 - 1/4 = 3/4 As area of AXCD is 3/4ar(ABCD), area of ABCD = 24 x 4/3 = 32cm²

We know that a diagonal divides a parallelogram into two triangles of equal area. Thus area of ABC = 1/2 ar(ABCD) or, ar(ABC) = 1/2 x 32 or, ar(ABC) = 16cm²

SO, ar.AXC=1/2 ar.ABC (CX is the median as X is the m.p.) ar.ABC=ar.ADC (AC is the diagonal and the diagonal divides the //gm into 2 cong.triangles) Ar.AXCD=1/2 ar.ADC+ADC AR.AXC=1/3 ADC=8cm^2 hence ar.ABC=8*2=16cm^2