Log in to add a comment

## Answers

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Simple harmonic motion is a type of periodic motion in which the restoring force acts directly proportional to the displacement and acts in the direction opposite to that of displacement. This is what happens in the motion of a simple pendulum.

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

For a motion to be in simple harmonic,

so for the pendulum to be in simple harmonic it should satisfy these two conditions.

lets go for it.

Condition 1:

1. Weight of the bob (W) acting vertically downward.

2. Tension in the string (T) acting along the string. The weight of the bob can be resolved into two rectangular components:

Since there is no motion along the string, therefore, the component

i.e.

Since

i.e.

In our assumption

Hence

Thus a is directly proportional to displacement.

Condition 2 :

The pendulum travels to and fro motion thus, it acquires Inertia due to which the displacement is opposite to acceleration.

__acceleration is directly proportional to displacement and it directs against the direction of displacement__,so for the pendulum to be in simple harmonic it should satisfy these two conditions.

lets go for it.

Condition 1:

**Acceleration is directly proportional to displacement**

1. Weight of the bob (W) acting vertically downward.

2. Tension in the string (T) acting along the string. The weight of the bob can be resolved into two rectangular components:

a.a.

**Wcosq along the string.**

b. Wsinq perpendicular to string.

b. Wsinq perpendicular to string.

Since there is no motion along the string, therefore, the component

**Wcosq**must balance tension (**T**)i.e.

**Wcosq****= T**This shows that only**Wsinq**is the net force which is responsible for the acceleration in the bob of pendulum. According to Newton's second law of motion**Wsinq**will be equal to**m**x**a**i.e.**Wsinq**=**m****a**Since

**Wsinq**is towards the mean position, therefore, it must have a negative sign.i.e.

**m a =**-**Wsinq**

But W =mg**-**

m a =m a =

**mgsinq****-**

a =a =

**gsinq**

In our assumption

**q**is very small because displacement is small, in this condition we can take**sinq =****q**

Hence

**a =**-**gq**Thus a is directly proportional to displacement.

Condition 2 :

**Acceleration***directs against the direction of displacement*The pendulum travels to and fro motion thus, it acquires Inertia due to which the displacement is opposite to acceleration.

**Thus it follows both the conditions and hence is in SHM**