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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

(i) The diameter of neck and bottom of a bottle are 2cm and 10cm respectively. The bottle is completely filled with oil. If the cork in the neck is pressed

in with a force of 1.2kgf, what force is exerted on the bottom of the bottle? (ii) A ball is thrown vertically upwards. It returns 6s later. Calculate : (i) the greatest height reached by the ball, and (ii) the initial velocity of the ball. (Take g = 10metre per second square).

I) The same force (1.2 kgf) would be exerted at the bottom of the bottle, as the force exerted in a fluid gets transmitted undiminished in all directions. (ii)Given, u=? v=0 g=-10m/s^2 returns after 6 seconds s=? If the ball returns after 6 s, then the time taken by it to reach the height is 6/2= 3s So, using first eq of motion, v=u+gt 0=u+(-10)*3 (here, g=-10 m/s^2 as the ball is thrown against gravity) -u=-30 m/s u=30m/s (initial velo) Now using third eq v^2=u^2+2gs 0=(30)^2+ 2 (-10)s 0=900-20s 20s=900 s=900/20=45 m