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Osmotic pressure of a 4.44% solution of anhydrous CaCl2 was found to be 16.42 atm at 27°C. What is the degree of dissociation of CaCl2 ?



Α(degree of dissociation )= i-1/n-1 Where i=van hoff factor n= no of moles after dissociation on calculating i=1.66 n=2 α=33.33%
2 5 2
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