Answers

2015-03-29T13:37:47+05:30
The equation oof a straight having intercept a and b on x and y axis is x/a+y/b=1
given that,
a+b=5
ab=6
(a-b)^2=(a+b)^2-4ab=(5)^2-4(6)=25-24=1⇒a-b=±1
we have a+b=5 and a-b=+1,a-b=-1
if we solve a+b=5 and a-b=+1 we get a=3,b=2
if we solve a+b=5 and a-b=-1 we get a=2,b=3
hence the equations are x/3+y/2=1 and x/2+y/3=1

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2015-03-29T14:33:37+05:30