Answers

2015-03-30T23:04:02+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Let the final temperature be T.
Heat lost by water at 40°C is gained by water at 20°C. Thus

m_1s \Delta T_1=m_2s \Delta T_2\\ \\ 50 \times s \times (40-T)= 50 \times s \times (T-20)\\ \\40-T=T-20\\ \\T+T=40+20\\ \\2T=60\\ \\T= \frac{60}{2}=30^0C

Final Temperature is 30°C
0
2015-03-31T05:45:51+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
by using the method of mixture formula,
final temperature T = M1×T1+M2×T2/ M1+M2

                             = 50×20 + 50×40/50+50
                             = 100+200/100
                             = 300/100
                             = 30 degrees c 
therefore final temperature T = 30 degrees C
1 5 1