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2015-03-31T23:01:40+05:30

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See the attachment.
Let the force acting on each leg on right side be F₂.
So total leg on right side = 2
total force = 2F₂

Since the bench is at equilibrium, moment at point A is 0. So
2F₁ × 0 - 75 × 0 - 170 × 2 - 160 × 3 + 2F₂ × 6 = 0 
⇒ 0 - 0 - 340 -480 + 12F₂ = 0
⇒ -820 + 12F₂ =0
⇒ 12F₂ = 820
⇒ F₂ = 820/12 
⇒ F₂ = 68.33 lb

Weight supported by each leg on right side is 68.33lb.
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