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The amount of air inside the cone equals the volume of the cone
radius of the cone,r = 7m
height of the cone, h = 12m
Volume of cone = 1/3πr²h
                       =1/3×22/7×7××12 m³
                       =28×22 m³
                      =616 m³      

Therefore, the amount of air inside the conical tent is 616 m³.
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the amount of air inside the conical tent=the vol.of the tent=1/3pi r^2 h
hence,the vol.= 1/3.pi.7².12=615.75216m³

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