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given that ,
   PQ // RS 
       - when we join AB through O we get AB as a transversal on PQ // RS 
        - diagonal PR is also a transversal 
     now ,  in Δ AOP &ΔBOR 
        ∠ PAO = ∠OBR ( alt. interior angles ) 
       ∠AOP = ∠BOR    ( v. opp. angles ) 
        ∠ APO = ∠ORB  ( alt. interior angles ) 
 by AAA    Δ AOP is congruent to ΔBOR  
  ⇒ ar. ΔAOP = ar. ΔBOR ( c.p.c.t ) 
     ( proved ) ......


1 5 1
i make fig. by
in MS paint and there i draw my figure by ruler , curve lines and other shapes and i attach to my answer thats easy
yeah understood
answer that ABCD Rhombus question
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