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Are these two different questions?

yes

please post the other one spending 10 points more...please

i m xplaining step wise

ok

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Step 1: x²-6/5 x -2/5 = 0 divding equation with 5

step 2 : x²-6x/5 = 2/5

step 3: x²-6x/5 + (3/5)² = 2/5 +(3/5)² adding (3/5)² on both sides

step 4: (x- 3/5)² = 2/5 + 9/25

step 5: (x- 3/5)² = 19/25

step 6: x-3/5=√19/√25

step 7: x = 3/5+√19/5

so x = 3__+__√19/5

s0 x = 3+√19/5 or 3-√19/5

this is the completing square method

step 2 : x²-6x/5 = 2/5

step 3: x²-6x/5 + (3/5)² = 2/5 +(3/5)² adding (3/5)² on both sides

step 4: (x- 3/5)² = 2/5 + 9/25

step 5: (x- 3/5)² = 19/25

step 6: x-3/5=√19/√25

step 7: x = 3/5+√19/5

so x = 3

s0 x = 3+√19/5 or 3-√19/5

this is the completing square method

So in

5x²-6x-2=0

divide the middle term by 2 and square the quotient so in here we get

5x²-6x+(3)²-2=0+9

we add 9 on the other so that there is no increments or decrements in the equation ,

STEP 2:

Now you would see that

=>

=>

Divide the equation by 5 (both side , so that the first term's coefficient becomes 1.

This gives x²- frac{6}{5} x+( frac{9}{5} ) = frac{11}{5}

So using the identity we form it as;

(x-3)²=11/5

so x=3+√11/5 or 3-√11/5