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A boat having a length 3 m and breadth 2 m is floating on water the boat sinks by I cm, when a man gets on it .What is the mass of the man ?



Volume of water displaced = (3 x 2 x 0.01) m3              [1cm =0.01 meter]
                                       = 0.06 m3.
 Mass of man = Volume of water displaced x Density of water
                    = (0.06 x 1000) kg
                    = 60 kg.
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We use the Archimedes law.
The additional volume of water displaced by the boat when the man gets onto it,
     = 3 m * 2 m * 1 cm = 0.06 m³

So  the weight of the man = weight of  0.06 m³ of water
             = 0.06 m³ * 1000 kg/m³
           = 60 kg

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