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A key is 5 cm long and turns a levers of the lock at the distance of 1 cm. If the lock is opened by an effort of 10 N, calculate the resistance offered by

the levers of the lock.Answer with complete procedure. Quick!!!!



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Force applied by you = 10N
length of key = 5cm
so force arm for you = 5cm

let resistance offered by levers of key = F
distance of levers = 1cm
so force arm for lever = 1cm

Balancing the moments,
10N × 5cm = F × 1cm
⇒ F = 50N

So resistance offered by the levers of the lock is 50N.
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